NPTEL Assignment

Question

Consider a direct-mapped cache with 64 blocks and a block size of 16 bytes. Byte address 1200 will map to block number ………… of the cache.

Answer 1

Block size = 16 B
Memory block number = Byte Address / Block size
= 1200/16 = 75

Cache block number = (Memory block number) mod (number of blocks in cache) 
= 75 mod 64
= 11 

Or

#CMBlock = 64 = 2^6 
Block Size = 16 = 2^4

Tag(x)

CLO(6) bits

Block Offset(4)

Convert 1200 in Binary : 10010110000 ==> 1 001011 0000
So Block Number = B11                       11