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If the size of the logical address space is $2^{m}$ and the page size is $2^{n}$ addressing units, then the high order $\text{m-n bits}$ of a logical address designate the _____________ .

  1. offset 
  2. page no 
  3. frame no
  4. physical address
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page number offset

                 m-n bit                                                              n nit

logical address space =2^m. so m bit require to represent the address space 

page size=2^n. so n bit require for offset.

so page number =m-n.

Ans is option B.

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