The answer would be option D.
The theorems required for this are elegantly explained in the following youtube link
https://www.youtube.com/watch?v=OjvF7OcdNiQ
$∑^{20}_{k=0}$(2k + 1)C(41, 2k + 1)
= 41* $∑^{20}_{k=0}$C(40, 2k)
Now the sum of Even terms would be equal to odd terms as per theorems in the youtube link hence each of those sums would be $2^{39}$
Hence the answer is 41 * $2^{39}$