Option elimination for this problem **only**

Total arrangements possible = 5! = 120

1 combination when all balls are at their respective places

so remaining arrangements = 120 - 1 = 119

this eliminates **Options C & D**

when B1 is placed at C1

no. of arrangements = 1 * 4 ! = 24

so remaining arrangements = 119 - 24 = 95

this eliminates **Options B **

**Use this method when you dont know how to solve the ques
and their is large difference in the given options like above options**