# pages = 8
page size = 512 Byte = frame size
# frames = 16
physical memory address consists of frame no.+ byte offset
for 16 frames 4 bit will be frame no. & since page size is 512 Bytes, byte offset = 9 bits.
physical address length = 4+9=13 bits.
Now, it can be seen from the page table that page no. 4 is having frame no. 3, which mean page no. 4 is in frame no. 3 of main memory.
And within the page we have to access byte no. 241.
so physical address will look like: 3,241->convert it to 13 bit binary->0011011110001=(1777) base 10.