1 votes 1 votes Digital Logic testbook-test-series + – rsansiya111 asked Dec 26, 2021 rsansiya111 308 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes option C i.e 5. let b be the radix. hence $(312)_{b} = (20)_{b} * (13.1)_{b}$ $3b^{2} + b + 2 = 2b * (b + 3 + b^{-1})$ $3b^{2} + b + 2 = 2b^{2} + 6b + 2$ $b^{2} – 5b = 0$ Now b >=4 since the max digit used is 3. Hence b ≠ 0. Hence b = 5 AngshukN answered Dec 26, 2021 AngshukN comment Share Follow See all 0 reply Please log in or register to add a comment.