1 votes 1 votes Host A is connected to host B with a 100 Mbps link that has a 200 ms one-way latency and transmission delay of 10 sec. How much data can A send to B before B’s first acknowledgement reaches A? Computer Networks test-series computer-networks data-link-layer + – LRU asked Dec 28, 2021 LRU 460 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes BW=100Mbps Tt=200ms Tp=10sec data that can transfer in 1sec : Tt=data/BW So, data=Tt×BW=200ms×100Mbps=20000000bits so, in 1sec we can transfer upto 20000000bits In 10sec= 20000000/10=2000000bits=2×10*6bits Onika answered Jan 4, 2022 Onika comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes B’s first acknowledgment reaches A at time = A’s transmission time + RTT = 10 sec + 400ms = 10.4 sec The link is 100 Mbps, In 1 sec ---- 100 * 10^6 bits of data can be sent in 10.4 sec --- 100*10^6 * 10.4 = 1400* 10^6 bits can be sent. Sam23 answered May 3, 2022 • edited Oct 28, 2022 by Sam23 Sam23 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes time before acknowledgement=Tt+2*Tp = 10 sec + 400ms = 10.4 sec 1 sec ---- 100 * 10^6 bits of data can be sent 10.4 sec --- ? 10.4*100*10^6 bits akash manikantha answered Jul 17, 2022 akash manikantha comment Share Follow See all 0 reply Please log in or register to add a comment.