1,494 views
0 votes
0 votes
A message consisting of $2400$ bits is to be passed over the Internet. The message is passed to the transport layer which appends a $150$ – bit header, followed by the network layer which uses a $120$ - bit header. Network layer packets are transmitted via two networks, each of which uses a $26-$bit header. The destination network only accepts up to $900$ bits long. The number of bits, including headers delivered to the destination network, is _________.

1 Answer

Best answer
3 votes
3 votes
Given:

Message size $= 2400$ bits.

The header of the transport layer $= 150$ bits.

Segment size at transport layer $=$ (Header + Message size) $= 150 + 2400 = 2550$ bits.

Maximum, transmission unit at destination network $= 900$ bits

 So, At a time, data supported by the destination network $= 900 \ – 26 = 874$ bits.

Hence, $2550$ bits are divided into packets having a maximum of $874$ bits.

But $874$ is not divisible by $8,$

So:

Length of packet $1 = 872$ bits.

Length of packet $2 = 872$ bits.

Length of packet $3 = 806$ bits.

Total  $= 2550$ bits.

Network layer packets are transmitted via two networks, each of which uses a $26$ – bit header. So, The number of bits, including headers delivered to the destination network is:

Packet $1$ (Data + Header) size $= 26 + 26 + 872 = 924$ bits.

Packet $2$ (Data + Header) size $= 26 + 26 + 872 = 924$ bits.

Packet $3$ (Data + Header) size $= 26 + 26 + 806 = 858$ bits.

Total $= 2706$ bits.
edited by

Related questions

0 votes
0 votes
0 answers
1
mridul_negi asked Feb 25
102 views
A packet has arrived in which the offset value is 100. Then what's the number of 1st Byte?
0 votes
0 votes
1 answer
2