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Consider a system with page size $\text{p}$ and average process size $\text{m}$ and size of each page table entry is $\text{e}.$ What is the amount of space required by page table ?

  1. $\text{me/p}$
  2. $\text{mp/e}$
  3. $\text{mpe}$
  4. $\text{pe/m}$
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PAGE TABLE SIZE = (TOTAL NO.OF PAGES) * PAGE TABLE ENTRY SIZE

                                = (PROCESS SIZE / PAGE SIZE) * PAGE TABLE ENTRY SIZE

                                = (m / p) * e 

 

option A is correct

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