0 votes 0 votes Consider a system with page size $\text{p}$ and average process size $\text{m}$ and size of each page table entry is $\text{e}.$ What is the amount of space required by page table ? $\text{me/p}$ $\text{mp/e}$ $\text{mpe}$ $\text{pe/m}$ Others nielit2021dec-scientista + – soujanyareddy13 asked Jan 9, 2022 edited Jan 17, 2022 by soujanyareddy13 soujanyareddy13 180 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes PAGE TABLE SIZE = (TOTAL NO.OF PAGES) * PAGE TABLE ENTRY SIZE = (PROCESS SIZE / PAGE SIZE) * PAGE TABLE ENTRY SIZE = (m / p) * e option A is correct SANDEEP171 answered May 10, 2023 SANDEEP171 comment Share Follow See all 0 reply Please log in or register to add a comment.