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Option $(D)$ is correct here.

  1. $A.\bar A=1$ is false. $A.\bar A=0$ is correct.
  2.  $A+AB=A+B$ is also false. $A(1+B)\implies A.1=A$
  3. $A(A+B)=B$ is false. $(A+AB)$ can be written as option $2$
  4. $A+\bar AB=A+B$ is true using distributive law.

$A+\bar AB\implies (A+\bar A)(A+B)\implies (A+B)$

 

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