This schedule is not in 2PL since X(A) in T2 can’t be acquired before releasing all the shared lock, If you release shared lock on A in T1 (before exclusive lock of T2) then you can’t acquire in final Read Request of T1. So this is not in 2PL.
Other explanation can be:
A 2PL schedule => conflict serializable
But the above schedule is not even conflict serializable (You can check it by swapping non conflicting pair, You will run into the issue with W2(A).)
So by contraposition (Not conflict schedule => not 2PL).
Hence the above schedule is neither 2PL nor conflict Serializable.
Regarding View Serializability: T1,T3 should come before T2 (Initial Read). But according to W R sequence of T1 and T2(Final 2 operations) T2 should come before T1 leading to contradiction. Hence Not View Serializable.
Hence the answer is D i.e. Schedule is not Serializable.