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Can anyone please solve this?

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Cache size=256KB= 2^18

Block size=32 KB=2^5

Number of blocks=(2^18)/(2^5)=2^13 blocks

14 bit(Tag) 13bit(index) 5 bit(Offset)

Total entry=14+1+1+=17bit

Total size of tag memory=17bit*2^13=136Kb=136/8=17KB

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