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Consider a message with 60000 bits long, that is to be sent from a source to a destination, there are two routers between source to destination. 

Each of link in the path has bandwidth 1 Mbps, each packet is 1000 bit long, total time taken (in msec) to reach the last bit to the destination, propagation delay is 10 msec ________.

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when first packet is transmitted on last link see the scenario


At t=22 it reaches second router
At t=23 it is transmitted from second router
At t=33 it reaches destination
At t=24 second packet is transmitted from second router
At t=34 second packet reaches destination
So every 1 second packet reaches destination.

That means 1st packet reaching destination at 33ms

remaining (60-1=59 packets) can reach the destination with= 59+33 =92ms.

So your analysis is correct Until last step. That means we will not consider the Propagation time for every packet. It should be Transmission time(59*Tt). Hope this helps.

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