optimal window size is when link utilization is 100% …
To find optimal window size for sender ,
we consider N=1+2a
= 1 ..…
where N = sender window size and a = Tp / Tt ..
Given, RTT between x and y as 60 ms
= (60 * 10-3 ) seconds
bandwidth of link between X and Y is 512 KBps
= (512 * 103 ) Bytes/seconds….
It is Full duplex channel, so total data send from x to y is
= (2* Tp) * Band Width
= RTT * band width
=( 60 * 10-3) * ( 512 * 103)
= 60 * 512
= 30720 Bytes….
## packet size = 64 bytes...
### Number of window require = 30720 / 64 = 480 ...
@@@ So optimal window size is N = 1+2a
In case optimal window size, we can indirectly say that maximum throughput should be achieved. It means link utilization is 100% in case of optimal window...
And as you said , window size is defined as number of frames sent in 1 RTT--> This is window size in terms of packets ....
we can say , optimal window size is 1 greater than number of frames send in 1 RTT .
See this thread also https://gateoverflow.in/107261/optimal-window-size …