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The round trip delay between A and B is given as 60 ms, and the bottleneck bandwidth of the link between A and B is 512 KBps. What is the optimal window size (in packets) if the packet size is 64 bytes and the channel is full duplex.

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@LRU

 

Optimal window size =(1+2a) where a =Tp/Tt …..

Full duplex link,

so window size = 2* Tp * Band Width

= 60 * 10-3 * 512*103

=30720 bytes…

 

packet size = 64 bytes...

 

window size in terms of packets = 30720 / 64 = 480….

 

optimal window size = 480+1= 481 ...

 

1. https://gateoverflow.in/144462/Cn-optimal-windows-size

 

 

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