Given order = 32 = $2^5$
Number of all abelian group up to isomorphism = number of ways to partition 5
There are total 7 ways to do so
5+0, 4+1, 3+2, 3+1+1, 2+1+1+1, 2+2+1, 1+1+1+1+1
So correct answers are options (1) (2) and (3) since it is asked which of the options is not the answer.
To know more about partitions, refer: https://en.wikipedia.org/wiki/Partition_(number_theory)