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Anyone with detailed solution?

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POSET always satisfy the property of reflexivity , anti-symmetricity and transitivity . So all these properties can be used for checking S1 and S2 .

Here in S1 pairs (2,3) and (3,2) are violating the anti-symmetric property hence S1 not a POSET.

In S2 there is no such violating pair and all of the above three properties satisfy , hence S2 is POSET.

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