0 votes 0 votes “While constructing the parsing table for various parser GOTO entries and SHIFT entries are identical, the only difference is in reduce and error entries”, Is this statement correct? GOTO entries will be more if the number of states is more. right? raja11sep asked Jan 28, 2022 raja11sep 254 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply palashbehra5 commented Jan 28, 2022 reply Follow Share the statement is true for SLR(1) and LALR(1) parser and incorrect for CLR(1). 1 votes 1 votes Isha_99 commented Jan 28, 2022 reply Follow Share @palashbehra5 For LR(0) and SLR(1) parsers too GOTO and Shift entries remain same for parsing table, only reduce entries differ. 2 votes 2 votes raja11sep commented Jan 28, 2022 reply Follow Share the difference in reduce entries → difference in error entries. 2 votes 2 votes raja11sep commented Jan 28, 2022 reply Follow Share @palashbehra5 @Isha_99 thanks 2 votes 2 votes Please log in or register to add a comment.