how to solve it
@Shaik Masthan
i think sir it is computer science and engineering semester exame
@Chandrabhan Vishwa 1 I think he is suggesting to be more accurate with the title like which specific cse exam
V is 16-bit integer.
$(369C)_{16}$ = $(0011011010011100)_{2}$
Left shift it by 4 places
$(0110100111000000)_{2} = (69C0)_{16}$
Correct answer: (2) 0x69C0