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Assume the base of the number is $x$.

Therefore,
$=> (4)x+(2)x=(11)x$
$=> 4x^0+2x^0=1x^1+1x^0$
$=> 4+2=x+1$
$=> 6=x+1$
$=> x=6-1$
$=>x=5$

Hence base should be 5 for the given expression.

Let the base be x

= $(4)_{x} + (2)_{x} = (11)_{x}$

= $4 + 2 = x + 1$

= $x = 6-1 = 5$

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