Institute of Technology, GNCTD

Question

If the average page-fault service time of 20 𝑚s, a 𝑀AT of 80 𝑛s and the probability of a page fault is 10 %. An effective access time will be:

 

2,000,672 𝑛s

2,000,072 𝑛s

2,000,036 𝑛s

2,000,006 𝑛s

Answer 1

Effective memory access time = $0.9*80 + 0.1*20*10^6$ ns

= $2,000,072$ ns