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In Dining philospher problem, there are X number of dinners and Y number of chopsticks. What is the minimum number of chopsticks required to insure that there will be no deadlock?

A) X

B) Y - X

C) Y - X + 1

D) [Y/2] + 1
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Answer should be A, which is X. I think here dinners is referring to the philosophers else question not making any sense.

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