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GO Classes 2023 | Weekly Quiz 6 | Question: 9

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What will be the output of the following program?

#include<stdio.h>
void swap(char **s1, char **s2){
    char *tmp;
    tmp=*s1;
    *s1=*s2;
    *s2=tmp;
}
int main()
{
    char *str[3]= {"orange", "apple", "pear"};
    for (int i = 0; i<2; i++)
        swap(&strs[i], &strs[i+1]);
    printf("%s %s %s", strs[0], strs[1], strs[2]);
}
  1. pear apple orange
  2. apple pear orange
  3. orange apple pear
  4. apple orange pea
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5 votes
5 votes

Answer: B

*str[3] is an array of pointers and it is like

After 1st iteration of the for loop content of str[0] and str[1] is swapped. It will be like

After 2nd iteration of for loop content of str[1] and str[2] is swapped. It will be like

Therefore it is printed in following order:

apple pear orange

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GO Classes 2023 | Weekly Quiz 6 | Question: 2
What will be the output of the following program? #include<stdio.h> main() { int a[2][3][4]; printf("%d", a[1][0]-a[0][2]); }
What will be the output of the following program?#include<stdio.h main() { int a [3][4]; printf("%d", a [0]-a[0] ); }
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