10 eggs distributed among A,B,C,D in the ratio 1:2:3:4 not necessarily in that order.
Since, $1+2+3+4 = 10,$ the $10$ eggs must be distributed as $1,2,3,4.$
Let us assume ,
No of eggs A gets =p
no of eggs B gets =q
no of eggs C gets=r
no of eggs D gets=s .
we can think it like a bijection function from {p,q,r,s} ->{1,2,3,4}
now it is given ,
- p<q
- s<r
now it is also given ,
p=q/2
so from this we can infer that q is either 4 or 2 as they both divide by 2 because it is guaranteed that p got some distributions of eggs.
case 1:- q=4
so, p=2 [ because p=q/2]
r=3
s=1 [ because s<r]
case 2:-
q=2
p=1 [because p=q/2]
r=4 [because s<r]
s=3
so this two are the possibility and we from can see here ,
C can have both even or odd number of eggs both are possible .
But D has to take necessarily odd number of eggs .
The two bijection can look like :-
So correct option is D.