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NIELIT 2022 April Scientist B | Section B | Question: 73

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Answer: C

$\sqrt{(224)}_r = (13)_r$

$\implies \sqrt{2r^2 + 2r+4} = r+3$

Squaring both side

$\implies 2r^2+2r+4 = r^2 + 6r + 9$ 

$\implies r^2 – 4r – 5 = 0$

$\implies (r+1)(r-5) = 0$

radix can’t be negative, therefore

$r=5$

 
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