retagged by
391 views
4 votes
4 votes

Let $\text{R}$ be the set of all real numbers.

Let $\text{S} = \text{R}\setminus \{-1\}$ and define a binary operation on $S$ by $a \ast b = a + b + ab.$

Which of the following is true?

  1. $(\text{R},\ast)$ is an abelian group, but $(\text{S},\ast)$ is not.
  2. $(\text{S},\ast)$ is an abelian group, but $(\text{R},\ast)$ is not.
  3. Both $(\text{R},\ast),(\text{S},\ast)$ are abelian groups.
  4. None of $(\text{R},\ast),(\text{S},\ast)$ are abelian groups.
retagged by

1 Answer

3 votes
3 votes

Both $(\text{R},\ast)$ and $(\text{S},\ast)$ are monoids, but $(\text{R},\ast)$ is not a group as for “$-1$” there is no inverse.


edited by
Answer:

Related questions

2 votes
2 votes
1 answer
3