Answer: (D) 616
Starting address(base address) for pixel location = 0, and given that pixel size = 1 bit.
Number of rows (r) = 100 – 0 + 1 = 101, Number of columns (c) = 100 – 0 + 1 = 101
In row-major-order fashion, address of element (i, j) = B + [(i – lr)*c + (j – lc)]*S
where B = Base address,
c = number of columns,
lr = row start index of 2D matrix,
lc = column start index of 2D matrix,
S = size of each element,
So, in row-major-order fashion, address of pixel (6, 10) = 0 + [(6-0)*101 + (10-0)]*1 = 616