GO Classes Test Series 2024 | Programming | Test 3 | Question: 15

GO Classes asked Apr 30, 2022 • retagged May 28, 2023 by Lakshman Bhaiya

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If the $32$-bit number given below is stored in little-endian at address $1000,$ what is the value of the byte at address $1002?$ Answer in decimal.
$$0001\; 0010 \;0011\; 0100\; 0101\; 0110\; 0111\; 1000$$
This number is the same as $12345678$ in hexadecimal.

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GO Classes asked Apr 30, 2022 • retagged May 28, 2023 by Lakshman Bhaiya

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Given 32b number 0x 12345678 is stored at location 1000 in little endian format.

At 1000, 0x 78 is stored (not 87).

At 1001, 0x 56 is stored.

At 1002, 0x 34 is stored.

At 1003, 0x 12 is stored.

At 1002, 0x 34 is stored, which is equivalent to 3 * 16 + 4 = 52 in decimal.

Answer :- 52

shishir__roy answered May 1, 2022

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abhijeetps

commented Oct 14, 2022

Why is is 78 and not 87? Can you please explain this part?
Thanks.

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shishir__roy

commented Oct 14, 2022

The endian system dictates whether we store MSB to LSB or LSB to MSB starting at some memory location.

$0x78$ is $1$ whole Byte, we do not alter the nibbles of a Byte, we store them as they are.

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