$2,-3,2,-1,2$
$F(\phi)$ = 0 and $F(push( S,i ))$ = $max(f(s),0) + i$;
initially, Stack is empty and For empty stack, $0$ is given
$push(S,i)$
$F(push(0,2)) = max( f( ∅) , 0) + 2 = max(0,0) + 2 = 2$ so $2$
$F(push(2,-3)) = max( 2 , 0) + (-3) = 2 -3 = -1$
$F(push(-1,2)) = max( -1 , 0) + 2 = 0 + 2 = 2 ,f(s ) = 2$ now
$F(push(2,-1)) = max( 2 , 0) + (-1) = 2 - 1 = 1 so f(s )= 1$ now
$F(push(1,2)) = max( 1 , 0) + 2 = 1 + 2= 3$
so 3 $Option\space C$ is correct