2 votes 2 votes No. of solutions to the following inequality 12 <= w + x + y + z <= 14 where w,x,y,z>=0 Combinatory combinatory discrete-mathematics counting + – khushitshah asked Jun 8, 2022 retagged Jun 8, 2022 by khushitshah khushitshah 394 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply khushitshah commented Jun 8, 2022 reply Follow Share The Idea I have is to solve this is: (no. of solution for w + x + y + z = 12) + (no. of solution for w + x + y + z = 13) + (no. of solution for w + x + y + z = 14) = 15C3 + 16C3 + 17C3 = 1695 is it correct? 2 votes 2 votes khushitshah commented Jun 8, 2022 reply Follow Share @Deepak Poonia sir please look into this 0 votes 0 votes Deepak Poonia commented Jun 10, 2022 reply Follow Share That’s correct @khushitshah . 1 votes 1 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes One of the method is have cases Case 1: w+x+y+z = 12 Case 2: w+x+y+z = 13 Case 3: w+x+y+z = 14. Upon applying IODB – star bar template no of solutions = = 15C3 + 16C3 + 17C3 Vineeth Rambhiya answered Jun 8, 2022 selected Jun 10, 2022 by Deepak Poonia Vineeth Rambhiya comment Share Follow See all 0 reply Please log in or register to add a comment.