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A table has fields $F_1, F_2, F_3, F_4, F_5$ with the following functional dependencies  

  • $F_1 \to F_3,  F_2\to F_4,   (F_1 . F_2) \to F_5$

In terms of Normalization, this table is in

  1. $1\;\text{NF}$
  2. $2\;\text{NF}$
  3. $3\;\text{NF}$
  4. None of these
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1) F1->F3
2) F2->F4
3) F1F2->F5

Candidate key: F1F2

As F1, F2 are prime attributes, they showcase partial dependency which makes the decomposition not 2NF, so its 1NF

Option (A)

Answer:

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