This schedule is not conflict serializable. Now we check for blinbd writes. Yes it has blind writes w1(x),w2(x). Now T1 says it reads initial value of x so in equivalent serial schedule T1 should occur first. Also the given schedule says T2 also reads initial value of x so in equivalent serial schedule T2 should occur first. So T1 occurs first before T2 and T2 occurs first before T1 which is actually not possible so given schedule is not view serializable. Also we can do by manually writing the schedules. As two transactions are there so possible serial schedules are
a) T1-->T2 r1(x),w1(x), r2(x),w2(x) - Here we see that T1 is reading initial value of x,the final write condition by T2 has been mainained bt T2 is unable to read initial value of x as it is modified by T1's w1(x).
b)T2-->T1 r2(x),w2(x), r1(x),w1(x) - Here we see that T2 is reading initial value of x, BUT the final write condition by T2 is not mainatined and also T1 is unable to read initial value of x as it is modified by T2's w1(x).
So IT IS NOT VIEW SERIALIZABLE.
PLS CORRECT ME IF I WRONG