I am not able to understand how the value of 'i' is 3 after the execution of the program, it must be 2.

Question

#include <stdio.h>

int main ()
{
    int i, j;
    int a [8] = {1, 2, 3, 4, 5, 6, 7, 8};
    for(i = 0; i < 3; i++) {
        a[i] = a[i] + 1;
        i++;
    }
    i--;
    for (j = 7; j > 4; j--) {
        int i = j/2;
        a[i] = a[i] - 1;
    }
    printf ("%d, %d", i, a[i]);
}

Comments

Why it should be 2 ?

Note that line no 12, has no effect on line 15

 

Trace line 6,7,8 step by step. Before entering into line no 10, i value is 4.

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Thank you.

Answer 1

answer is 3, 2