Since $-13.5$ is negative number so $s = 1$
Exponent = $7$ bits, therefore bias = 63
$13.5$ in binary = $1101.1$ = $1.1011 * 2^3$
E = e + bias = $3 + 63$ = $66$ = $1000010$
We store number like
S (1bit) |
E (7 bits) |
M (8bits |
$(1100001010110000)_{2}$ = $(C2B0)_{H}$