Calculating frame length when bit rate, propagation delay(in bits) and length of link is given.

Purple asked Jan 26, 2016

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Assume CSMA/CD protocol. Find the least frame length in bytes for a 2 Mbps bit rate and 1.5km long network where propagation delay is 4.25 nano seconds per metre _______

Computer Networks
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csma-cd

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Purple asked Jan 26, 2016

Purple

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TT=2PT

TT= frame length/ bandwidth= frame length/2mbps

PT=4.25nsx1.5km= 6.375μs

TT=2PT

Framelength/2x10⁶= 2x6.375μs

Framelength= 4x6.375= 25.5bits= 3.18 byte

But I m lilbit confused about least frame length here.

khushtak answered Jan 26, 2016

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Purple

commented Jan 26, 2016

The least frame length will be 3 or 4?

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nikhil1008

commented Mar 24, 2016

why did you use 2*TT , it should be TT only right ?

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abhishek14893

commented Jun 26, 2017

3 should b the answer

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arch

commented Nov 17, 2017

you have took 4.25 nanosec per km but in question it is given 4.25 nanosec per meter.

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