1 votes 1 votes The roots of the polynomial $p(x)=x^{4}-2x^{3}-2x^{2}+8x-8$ are: $1, -1, 2, 2+3 i$ $1+i, 1-i, 2, -2$ $1, -1+i, 2, 2+3 i$ $1+i, -1+i, 2, -2$ Others cmi2021-datascience + – admin asked Jul 23, 2022 • edited Aug 8, 2022 by Lakshman Bhaiya admin 304 views answer comment Share Follow See 1 comment See all 1 1 comment reply ankitgupta.1729 commented Jul 28, 2022 reply Follow Share $x^4 – 2x^3 – 2x^2 + 8x – 8$ $x^3 (x – 2) -2 (x^2 -4x +4)$ $x^3 (x – 2) -2(x-2)^2$ $(x-2)(x^3 – 2(x-2))$ $(x-2)(x^3 – 2x+4 +4 -4)$ $(x-2)(x^3 +8 -2x-4)$ $(x-2)(x^3 +2^3 -2(x+2))$ $(x-2)((x+2)(x^2 +4-2x) -2(x+2))$ $(x-2)(x+2)(x^2 -2x +2)$ $(x-2)(x+2)(x- (1\pm i))$ 1 votes 1 votes Please log in or register to add a comment.
2 votes 2 votes Answer is option B we will see why [ Jiren ] answered Jul 28, 2022 [ Jiren ] comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes the rule for imaginary root exists in conjugate pair means if (a+ib) then other is (a-ib) only follow the (B) option. amit166 answered Jan 2, 2023 amit166 comment Share Follow See all 0 reply Please log in or register to add a comment.