Let $E$ and $F$ be events such that $P\left(E \cap F^{c}\right)=0.2, P\left(F \cap E^{c}\right)=0.3, P\left((E \cap F)^{c}\right)=0.7$, where, for an event $E$, the notation $E^{c}$ denotes the complement of the event. Then we can conclude that
- $P(E \cup F)=0.8$.
- $P\left(E^{c} \cap F^{c}\right)=0.3$.
- $P(F)=0.6$.
- $P(E)=0.6$.