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For a cyclic group $\text{G}$ of order $12$, the number of subgroups of $\text{G}$ is

  1. $2$

  2. $6$

  3. $8$

  4. $11$

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Lagrange's Theorem: In any finite group G, the order (number of elements) of every subgroup of G divides the order of G. 

Here G is the group with an order $12$.So it’s factor are: $1,2,3,4,6,12$

$\therefore 1,2,3,4,6,12$ six subgroups are there.

Lagrange's Theorem-based question:

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