GO Classes Scholarship 2023 | Test | Question: 24

Answer 1

magic(5, 5) is being called

It will print magic if if condition evaluates to true,

$\therefore$ x =5 and y = 5

 

Option A: $!(x==5) != !(y==5)$

                 $ !\text{T} != !\text{T} \implies \text{F} != \text{F}$ i.e. $False$

 

Option B: $(x==5)?!(y==5):(x==5)$

                Since x==5 is true so it will execute $!(y==5)$ i.e. $!True = False$ 

 

Option C:  $((x==5) || (y==5)) \& \& !((x==5) \&\& (y==5)) $

                      $True$ $\& \&$ $!(True)$ $\implies True \&\& False \implies False$

 

Therefore (D) is correct.

Comments

typo: option B:

“it will execute $!(y==5)$” (you’ve written x instead of y)

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just a correction @Aditya_ 

In option B , 

 Since x==5 is true, so it will execute !(y==5)