Why are we not considering the number of ways that 5 number can be given to that 5 players i.e. 5! ?

Isn’t that need to be included, cause for each 5 distinct arrangement, there will be D5 = 44 ways the dealer can loose.

Isn’t that need to be included, cause for each 5 distinct arrangement, there will be D5 = 44 ways the dealer can loose.