Let $A$ be a matrix of size row $\times$ col. $A$ has to be filled in a spiral clockwise fashion with successive integers from $1,2, \ldots$, row $\times$ col starting from the top left corner. For example, a $3 \times 4$ matrix should be filled in as follows: $$\begin{array}{cccc}1 & 2 & 3 & 4 \\ 10 & 11 & 12 & 5 \\ 9 & 8 & 7 & 6\end{array}$$ Fill in all the blanks in the following code snippet to do the above job. In the answer script, write only the while loop with the blanks filled-in.
#include<stdio.h>
#include<stdlib.h>
#define RIGHT 0
#define DOWN 1
#define LEFT 2
#define UP 3
void spiralFill ( int **A, int r, int c) {
int i, j, top, bottom, left, right, dir, k=1;
i = j = 0; dir = RIGHT;
top = 0; bottom = r-1; left = 0; right = c-1;
while ((top <= _______ ) && (left <= _______ )) {
A[i][j] = k; k++;
switch (dir) {
case RIGHT: if(j < _______) _______;
else{dir = _______; top = _______; i = _______;}
break;
case DOWN: if(i < _______) _______;
else{dir = _______; right = _______; j = _______;}
break;
case LEFT: if(j > _______) _______;
else{dir = _______; bottom = _______; i = _______;}
break;
case UP: if(i > _______) _______;
else{dir = _______; left = _______; j = _______;}
break;
}
}
}
int main() {
int **A, row, col, i, j;
printf("\n Row and column size::>");
scanf("%d %d", &row, &col);
A = (int **) calloc(row,sizeof(int *));
for(i=0;i<row;i++){
A[i] = (int *)calloc(col,sizeof(int));
}
spiralFill(A,row,col);
}
