0 votes 0 votes Consider an $n \times n$ matrix $A=I_{n}-\alpha \alpha^{T}$, where $I_{n}$ is the identity matrix of order $n$ and $\alpha$ is an $n \times 1$ column vector such that $\alpha^{T} \alpha=1$. Prove that $A^{2}=A.$ Others isi2019-pcb-mathematics descriptive + – admin asked Aug 8, 2022 edited Aug 27, 2022 by Lakshman Bhaiya admin 102 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes We just have to use the given condition for alpha Godlike answered Aug 9, 2022 Godlike comment Share Follow See all 0 reply Please log in or register to add a comment.