How many ways are there to distribute 5 distinct toys among 3 children such that every child gets at least 1 toy?
answer given is 150.
but I’m getting 9.
My approach go as follows:
step-1 : give 1 toy to all 3 children, now, I am left with (5-3) = 2 toys. Therefore, now I have to distribute 2 toys among 3 children.
step-2 : for toy1, I can give it to first child or second child or third child. Similarly, I can give toy2 to either of first or second or third child.
thus, toy1 has 3 choices and so do toy2. Therefore, my answer would be 3*3 = 9.
U will be missing a lot of cases because the toys are not identical to begin with