3 votes 3 votes Evaluate $y^{\prime \prime}(1)$ where $y=e^{x}+x^{e}$. $0$ $1$ $e^{2}$ $e$ Calculus goclasses2024-calculus-1 goclasses calculus differentiation 1-mark + – GO Classes asked Aug 28, 2022 edited Apr 29, 2023 by Lakshman Bhaiya GO Classes 399 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
4 votes 4 votes $y^{\prime}=e^{x}+e x^{e^{-1}}$ $y^{\prime \prime}=e^{x}+e \cdot(e-1) x^{e-2}$ $y^{\prime \prime}(1)=e+e^{2}-e=e^{2}$ GO Classes answered Aug 28, 2022 GO Classes comment Share Follow See all 0 reply Please log in or register to add a comment.