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GO Classes Test Series 2023 | Calculus | Test 1 | Question: 4

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$f(-x)=\cos (-x)-(-x)=\cos x+x$ (remember that $\cos (-x)=\cos x !)$. We have
$$
\begin{gathered}
\cos x+x \neq f(x) \\
\cos x+x \neq-f(x)
\end{gathered}
$$
Therefore $f(x)$ is neither even nor odd.
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