1.3k views

What is the output printed by the following program?

#include <stdio.h>

int f(int n, int k) {
if (n == 0) return 0;
else if (n % 2) return f(n/2, 2*k) + k;
else return f(n/2, 2*k) - k;
}

int main () {
printf("%d", f(20, 1));
return 0;
}

1. $5$
2. $8$
3. $9$
4. $20$
edited | 1.3k views

See the following calling sequence:

edited
+2
How is it f (10,2)-1 ??? When its given for every even N we have +k and for every odd n we have -k

0
Can anybody pls explain how the series values comes?
+1
it is if (n % 2) return f(n/2, 2*k) + k
which means n%2 must be 1 for condition to be true.I think you mistook it for if (n%2==0) 
The sequence has to be followed.

6.) f(20,1) = 9.

5.) f(10,2) - 1 = 9

4.) f(5,4) - 2 = 10

3.) f(2,8) + 4 = 12

2.) f(1,16) - 8 = 8

1.) f(0,32) + 16 = 16
0
Why have u executed else part in 5th step I guess else if has to be executed since 10 which is divisible by 2.
+9

else if (n%2)

This will be true if n is NOT a multiple of 2. When n is a multiple of 2, n%2 returns 0 and if will be false.

+1
Thank you sir.
0
how values are come i mean like 9,10,8.,16 etc.Anybody plz explain?
0
Can anybody plzz explain how this series values comes.
0
its clear now.
0
Else if (n%2) when n is multiple of 2 it will be like else if (0) therefore it will return false and will execute next else and   return f(n/2,2*k) - K....

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