The first marble can be picked out in $n$ ways and the second one in $n-1$ ways, the total number of ways of picking $2$ marbles will be $n(n-1)$ ways.
For getting 2 marble of the same colour the first one can be selected in $\binom{2m}{1}$ way and the second marble can be selected in only $1$ way(the same colour as the first draw), the total number of ways of picking 2 marble of the same colour will be $2m×1 = 2m$ ways.
Probability that both marbles are of same colour = $2m/n(n-1)$
Hence, option C is the correct answer.