in Computer Networks retagged by
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in Computer Networks retagged by
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4 Comments

The question seems right. Try to use basic concepts.
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@Vishal_kumar98 Sorry man, can’t seem to solve it. If you think this is correct, can you solve it, please?

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@Vishal_kumar98 please correct If I am wrong

I think, we can make in class B, 

4 subnets of 63 hosts with network 193.1.0.0

 and 4 subnets of 63 hosts in network 193.1.1.0 

with subnet mask 255.255.0.0

193.1.0.0 to 193.1.1.255

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1 Answer

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This is class C network. So, first 3 octet is for net ID and  last octet is host ID. for subnetting into 8 subnet 3 bits are taken from last octet (Host ID bits).

 

 

 

 

 

 

 

 

|--- subnet-----||-------- Host ID bits------|

As we have only 5 bits left in Host we cannot allot 63 hosts to each subnet.