0 votes 0 votes Number of solutions are there of x+y+z=17 in positive integers are_________ Here in this do we have to take constraints of x>=1,y>=1,z>=1? Combinatory made-easy-test-series engineering-mathematics discrete-mathematics combinatory + – UK asked Jan 28, 2016 • edited Mar 5, 2019 by akash.dinkar12 UK 944 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments Registered user 7 commented Jan 28, 2016 reply Follow Share this aanswer correct or wrong reply 0 votes 0 votes UK commented Jan 28, 2016 reply Follow Share Yes it is correct @Registered user 7 0 votes 0 votes Aboveallplayer commented Oct 27, 2016 reply Follow Share how we are getting 14 here i mean write the steps of the equation please 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes X1+X2+X3= 17 $X_{I}>=1 , I =1,2,3$ I can write X1+X2+X3= 14 as $X_{I}>=0$ Using multinomial theorem $\binom{n-1+r}{r}$ $\binom{3-1+14}{14}$ =120 ans sid1221 answered Jun 6, 2017 sid1221 comment Share Follow See all 2 Comments See all 2 2 Comments reply Hira Thakur commented Jan 15, 2018 reply Follow Share how 17 change to 14? 0 votes 0 votes sid1221 commented Jan 15, 2018 reply Follow Share they said x,y,z are positive integer so i cant take o so x>=1, y>=1,z>=1 thats why i minus 3 from RHS side also ... 0 votes 0 votes Please log in or register to add a comment.