**Correction **number of divisors should be $(6+1)(1+1)(1+1) $

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${if\ the\ element\ of\ a\ group\ G\ is\ order\ n,then\ a}^{m}=e\ if\ and\ only\ if\ n\ is\ divisor\ of\ m$

this is a property of subgroup

*so in ques have to find number of subgroups*

$m\leqslant 960$

*factors of m =* $2^{6}*3^{1}*5^{1}$

*possible value of m = number of divisors of m*

*$=(6+1)*(1+1)*(1+1)$*

*$=28$*